Compare youraverage value to the accepted value.

Latent Heat of Fusion of Ice– Data Analysis Worksheet1) Please take a picture of your apparatus at the end of one of the experiments and upload it in thespace below by clicking on the box below.2) Analysis Method (For simplicity we assume the heat absorbed by the ice from the coffee cup andenvironment is negligible, this assumption reduces the accuracy of the experiment)Ice is colder than warm water so energy will be transferred by heat to it from the warm water. Themelting of the ice can be considered to occur in two stages, first the ice at 0°C melts (phase change withno temperature change) into water at 0°C. The temperature of the warm water will drop as a result of itloosing energy to the ice. Then the water from the melted ice absorbs more heat from the warm waterfurther dropping the temperature of the warm water until both the melted ice and warm water reachthe same temperature (equilibrium), at that point, no more energy flows as heat between them as thereis no temperature difference. This is illustrated below.Ice at 0°C Water at 0°C Water at TfWarm Water at Ti Water at TfEnergy flow 1 (E1) Energy flow 2 (E2)Latent Heat of Fusion of Ice-Data Analysis Worksheet2For each experiment perform the following calculations:Experiment 1:a) Mass of empty coffee cup (grams) (mcup) ______________ gb) Mass of coffee cup and warm water (grams) (mcw) ______________ gc) Mass of warm water (subtract line a from line b) (mw) ______________ gd) Initial temperature of warm water (°F) ______________°Fe) Initial temperature of warm water in (°C):(to convert °F into °C, subtract 32 and divide the result by 1.8) (Ti) ______________°Cf) final temperature of water at equilibrium(°F) ______________°Fg) Initial temperature of warm water in (°C):(to convert °F into °C, subtract 32 and divide the result by 1.8) (Tf) ______________°Ch) Mass of coffee cup with water and melted ice (grams) ______________ gi) Mass of ice added (grams) [subtract line b from line h] (mi) ______________ gj) Energy lost by warm water to the ice= (mw*(Ti-Tf)) __________caloriesk) Energy gained by melted ice to warm to Tf =(mi*(Tf-0)) (E2) __________caloriesl) Energy absorbed by ice during melting step:subtract line (k) from line (j) (E1) __________caloriesm) Latent Heat of Fusion of ice=E1/mi(divide line l by i) Lf __________calories/gLatent Heat of Fusion of Ice-Data Analysis Worksheet3Experiment 2:a) Mass of empty coffee cup (grams) (mcup) ______________ gb) Mass of coffee cup and warm water (grams) (mcw) ______________ gc) Mass of warm water (subtract line a from line b) (mw) ______________ gd) Initial temperature of warm water (°F) ______________°Fe) Initial temperature of warm water in (°C):(to convert °F into °C, subtract 32 and divide the result by 1.8) (Ti) ______________°Cf) final temperature of water at equilibrium(°F) ______________°Fg) Initial temperature of warm water in (°C):(to convert °F into °C, subtract 32 and divide the result by 1.8) (Tf) ______________°Ch) Mass of coffee cup with water and melted ice (grams) ______________ gi) Mass of ice added (grams) [subtract line b from line h] (mi) ______________ gj) Energy lost by warm water to the ice= (mw*(Ti-Tf)) __________caloriesk) Energy gained by melted ice to warm to Tf =(mi*(Tf-0)) (E2) __________caloriesl) Energy absorbed by ice during melting step:subtract line (k) from line (j) (E1) __________caloriesm) Latent Heat of Fusion of ice=E1/mi(divide line l by i) Lf __________calories/gLatent Heat of Fusion of Ice-Data Analysis Worksheet4Experiment 3:a) Mass of empty coffee cup (grams) (mcup) ______________ gb) Mass of coffee cup and warm water (grams) (mcw) ______________ gc) Mass of warm water (subtract line a from line b) (mw) ______________ gd) Initial temperature of warm water (°F) ______________°Fe) Initial temperature of warm water in (°C):(to convert °F into °C, subtract 32 and divide the result by 1.8) (Ti) ______________°Cf) final temperature of water at equilibrium(°F) ______________°Fg) Initial temperature of warm water in (°C):(to convert °F into °C, subtract 32 and divide the result by 1.8) (Tf) ______________°Ch) Mass of coffee cup with water and melted ice (grams) ______________ gi) Mass of ice added (grams) [subtract line b from line h] (mi) ______________ gj) Energy lost by warm water to the ice= (mw*(Ti-Tf)) __________caloriesk) Energy gained by melted ice to warm to Tf =(mi*(Tf-0)) (E2) __________caloriesl) Energy absorbed by ice during melting step:subtract line (k) from line (j) (E1) __________caloriesm) Latent Heat of Fusion of ice=E1/mi(divide line l by i) Lf __________calories/gLatent Heat of Fusion of Ice-Data Analysis Worksheet53) Summary of resultsExperiment Lf (calories per gram)#1#2#3average4) The accepted value for the Latent Heat of Fusion of Ice is 79.4 calories/gram. Compare youraverage value to the accepted value. Comment on the success of your experiment. Does theassumption that the heat absorbed from the coffee cup and the surroundings is negligible leadto an overestimate or an underestimate of the Latent Heat of Fusion from the experiment?